The sum of two numbers is 20 the difference between three times the first number and twice the second is 40

one number x= 16

other number y = 4

Step-by-step explanation:

Lets say two number x and y

x + y = 20

3x - 2y = 40

solve for x first

first equation you get

y = 20 - x

now plug into second equation

3x - 2(20 - x) = 40

3x - 40 + 2x = 40; add x's and add 40 to both sides

5x = 80; divide by 5

x = 16; now plug this into the first equation

x + y = 20

16 + y = 20; subtract 16 to both sides

y = 4

now check into original equations

x + y = 20 ; 16 + 4 = 20; true

3x - 2y = 40; 3(16) - 2(4) = 40 ; 40 - 8 = 40; true

the answer is 8/21

hope this