If x^2 -7x=30 and x>0, what is the value of x-5

5

Step-by-step explanation:

x^2-7x=30

x^2-7x-30=0

a = 1, b = -7, c = -30

sqrt(b^2-4ac)

sqrt(49+120)

sqrt(169)

13

-b +/- 13

7 + 13 = 20

7 - 13 = -6

2a = 2

20/2 = 10

-6/2 = -3

we know x>0, so it cant be -3. so now its just 10 - 5

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation:

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.