Gina willson all about algebra (TRIANGLES ANGLES SUM) HELP ASAP PLEASE

14. Question wise,

In ΔRST,

∠R=2x+5

∠S=x+1

∠T=7x-16

we know,

∠R+∠S+∠T=180 [sum of 3 angles of a triangle is 180°]

2x+5+x+1+7x-16=180

10x-10=180

10(x-1)=180

x-1=18

x=19

so,

∠R=(2×19)+5=43

∠S=19+1=20

∠T=(7×19)-16=117

15. Question wise,

In ΔABC,

∠A=∠C-13

∠B=4∠C-11

we know,

∠A+∠B+∠C=180 [,,]

∠C-13+4∠C-11+∠C=180

6∠C-24=180

6∠C=180+24

∠C=204÷6=34

so,

∠A=34-13=21

∠B=(4×34)-11=125

16. Question wise,

In ΔJKL

∠K=∠J+9

∠L=2∠J-21

we know,

∠J+∠K+∠L=180

∠J+∠J+9+2∠J-21=180

4∠J-12=180

4∠J=180+12

∠J=192÷4=48

so,

∠K=48+9=57

∠L=(2×48)-21=75

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?