A sequence of transformations maps AABC onto AA'B'C'. The type of transformation that maps AABC onto AABC is a When ABC is reflected across the line x=-2 to form AA'B'C', vertex
of AB'C' will have the same coordinates as B.

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

it is part of the rising action that reveals public sentiment toward hester.

explanation:

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]