Melissa buys 212 pounds of salmon and 114 pounds of swordfish. She pays a total of $31.25, and the swordfish costs $0.20 per pound less than the salmon. What would be the combined cost of 1 pound of salmon and 1 pound of swordfish? A. $15.60 B. $15.80 C. $16.60 D. $16.80

C. $16.60

Step-by-step explanation:

Let the cost per pound of salmon be represented by x

The cost per pound of swordfish be represented by y

Melissa buys 2 1/2 pounds of salmon and 1 1/4 pounds of swordfish. She pays a total of $31.25

2.5 × x + 1.25× y = $31.25

2.5x + 1.25y = 31.25

The swordfish costs $0.20 per pound less than the salmon.

y = x - 0.20

Hence, we substitute

2.5x + 1.25y = 31.25

2.5y + 1.25(x - 0.20) = 31.25

2.5y + 1.25x - 0.25 = 31.25

2.5x + 1.25x = 31.25 + 0.25

3.75x = 31.5

x = 31.5/3.75

x = $8.4

The cost per pound of salmon be represented by x = $8.4

y = x - 0.20

y = 8.4 - 0.20

y = $8.2

The cost per pound of swordfish be represented by y = $8.2

The cost of a pound of salmon and sword fish

= $8.4 + $8.2

=$16.60

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

b if for most of the graph

d if y intercept

step-by-step explanation: