Suppose you have a bag of red, blue, and yellow marbles. If the probability of picking a red marble is start fraction 1 over 6 end fraction and the probability of picking a yellow marble is one-half, what is the probability of picking a blue marble? A. one-fourth B. one-third C. two-thirds D. one-eighth

B. one-third

Step-by-step explanation:

Probability of picking a red marble, P(R) = 1/6

Probability of picking a yellow marble, P(Y) = 1/2

Therefore, the probability of picking a blue marble will be:

= 1 - (P(R) + P(Y))

= 1 - (1/6 + 1/2)

= 1 - (4/6).

= 1 - 2/3

= 1/3

The probability of picking a blue marble will be one third

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.