Mitchell needs to buy some wood to build a rectangular box that is 12 inches long 8 I ches wide and 10 inches high a net of the box is shown how many square inches of wood would Mitchell need to build the box

592 in²

Step-by-step explanation:

Given

Length of the box L = 12 inches

Width W = 8 inches

height H = 10inches

Required

Surface Area of the box

Surface area of the rectangular boss = 2(LW + LH + WH)

Substitute the given values

Surface area = 2(12(8)+12(10)+8(10))

Surface Area = 2(96+120+80)

Surface Area = 2(96+200)

Surface area = 2(296)

Surface area = 592 in²

Hence  592 in² of wood would be needed by Mitchell to build the box

mental cunning

explanation:

he is often referred to as a man of twists and turns

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}