A regression by a sample of 10 observations gives: Score=49.5+1.96 Study Hours. The sample mean of study hour is 10.5 and sum of the squared deviations of this independent variable is 264.5. Now, what is the leverage statistic for study hour=14?

0.1463

Step-by-step explanation:

Number of observations = 10

Sample mean = 10.5

Sum of standard deviation = 264.5

X = 14

We are to calculate The leverage statistic for study hour 14 using the data above

= 1/10 + (14-10.5)²/264.5

= 1/10 + 3.5²/264.5

= 0.1 +12.25/264.5

= 0.1+0.04631

= 0.1463 is the leverage statistic for the study

i cant see the graph

step-by-step explanation: