Wilbur and eugene are selling cheesecakes for a school fundraiser customers can buy french silk cheesecakes and apple cheesecakes wilbur sold 13 french silk cheesecakes and 12 apple cheesecakes for a total of $331 eugene sold 2 french silk cheesecakes and 3 apple cheesecakes for a total of $74 what is the cost each of one french silk cheesecake and one apple cheescake

one french silk cheesecake = $7

one apple cheescake = $20

Step-by-step explanation:

Let the cost of one french silk cheesecake be represented by a

Let the cost of one apple cheescake be represented by b.

We are told that wilbur sold 13 french silk cheesecakes and 12 apple cheesecakes for a total of $331 . This can be written as:

13a + 12b = 331 equation i

Eugene sold 2 french silk cheesecakes and 3 apple cheesecakes for a total of $74. This can be written as:

2a + 3b = 74 equation ii

13a + 12b = 331 equation i

2a + 3b = 74 equation ii

Multiply equation i by 2

Multiply equation ii by 13

26a + 24b = 662 equation iii

26a + 39b = 962 equation iv

Subtract equation iv from iii

-15b = -300

b = 300/15

b = 20

The cost of one apple cheescake is $20.

From equation ii,

2a + 3b = 74

2a + 3(20) = 74

2a + 60 = 74

2a = 74 - 60

2a = 14

a = 14/2

a = 7

The cost of one french silk cheesecake is $7.

to determine the unit cost your would divide the total cost by the number sold.

7 bagels for $4.41       $4.41/7 = $.63 each at fresh side

5 bagels for $3.60         $3.60/5 = $.72 each at value mart

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west