Point P′(−3, 2) is the image of point P(3, 8) under a translation. What
is the image of (0, −6) under the
same translation?

The image of (0, -6) after the same transformation is (-6, -12)

Step-by-step explanation:

After the required translation, the given image of the given point P(3, 8) is P'(-3, 2)

Therefore, the translation of preimage P(3, 8) to the image P'(-3, 2) is given by the difference between the coordinates as follows;

The translation from P(3, 8) to P'(-3, 2) = T(-3 - 3, 2 - 8) = T(-6, -6)

Therefore after the same translation, the preimage of (0, -6) will have an image given as follows;

Coordinate of preimage (0, -6) → T(-6, -6) (0, -6) = (0+ -6, -6 + -6) → Coordinate of image (-6, -12)

The image of (0, -6) after the same transformation = (-6, -12).

b, i believe, but not sure.

answer: idk wbu

step-by-step explanation: umm..