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Mathematics, 03.11.2020 21:50 harlon852

Solve to find the value for x in the linear equation: 3(βˆ’4x + 5) = 123(βˆ’4x) + 3(5) = 12 βˆ’12x + 15 = 12

βˆ’12x + 15 βˆ’ 15 = 12 βˆ’ 15

βˆ’12x = βˆ’3

x =

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Solve to find the value for x in the linear equation: 3(βˆ’4x + 5) = 123(βˆ’4x) + 3(5) = 12 βˆ’12x + 15 =...
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