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Mathematics, 03.11.2020 21:50 harlon852
Solve to find the value for x in the linear equation: 3(β4x + 5) = 123(β4x) + 3(5) = 12
β12x + 15 = 12
β12x + 15 β 15 = 12 β 15
β12x = β3
x =
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Solve to find the value for x in the linear equation: 3(β4x + 5) = 123(β4x) + 3(5) = 12
β12x + 15 =...
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