In the diagram, lines AB , CD, and EF intersect at G

D. 70°

Step-by-step explanation:

Given:

m<DGB = 35°

m<CGF = 75°

Required:

m<AGE

SOLUTION:

m<EGD = m<CGF (vertical angles are congruent)

m<EGD = 75°

m<AGE + m<EGD + m<DGB = 180° (angles on a straight line)

m<AGE + 75° + 35° = 180° (substitution)

m<AGE + 110° = 180°

Subtract 110 from each side of the equation

m<AGE = 180° - 110°

m<AGE = 70°

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.