Ramon would like to plant a garden where each row has the same combination of plants. If Ramon has 36 tomato plants, 24 cucumber plants, and 18 basil plants, what is the greatest number of rows the garden can have if he uses all of the plants?

6 rows

Step-by-step explanation:

We are told in the qiestion: Ramon has 36 tomato plants, 24 cucumber plants, and 18 basil plants.

We are to find the greatest number of rows the garden can have if he uses all of the plants.

We solve using Greatest Common Factor method.

We find the factors of 18, 24 and 36

The factors of 18 are: 1, 2, 3, 6, 9, 18

The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

Then the greatest common factor is 6.

The greatest number of rows the garden can have if he uses all of the plants is 6 rows

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

y=mx+