A recent survey found that 80.5% of households has Internet access and 82% of households had cable television. Also, it was reported that 74.7% of households had both Internet access and cable television. Determine the probability that a randomly selected household in the survey had either Internet access or cable'

0.878

Step-by-step explanation:

Given : P( Internet access) = 80.5%= 0.805

P(cable television) = 82% = 0.82

P( Internet access and cable television) = 74.7% =0.747

Formula: P(A or B)= P(A ) + P(B) - P(A and B)

So, P( Internet access or cable television)  =  P( Internet access)  + P(cable television) -P( Internet access and cable television)

= 0.805+0.82-0.747

=  0.878

The probability that a randomly selected household in the survey had either Internet access or cable = 0.878

answer: approximately 206 bones

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