Prove that d dx (sinh−1(x)) = 1 1 + x2 . Solution 1 Let y = sinh−1(x). Then sinh(y) = x. If we differentiate this equation implicitly with respect to x, we get dy dx = 1. Since cosh2(y) − sinh2(y) = 1 and cosh(y) ≥ 0, we have cosh(y) = 1 + sinh2(y) , so dy dx = 1 cosh(y) = 1 1 + sinh2(y) = . Solution 2 From the equation sinh−1(x) = ln  x + x2 + 1 , we have d dx  (sinh−1(x)) = d dx  ln x + x2 + 1 = 1 x + x2 + 1   d dx   x + x2 + 1 = 1 x + x2+ 1   1 + x x2 + 1 = x2 + 1 + x x + x2 + 1   x2 + 1 = 1 x2 + 1 g

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

positive

step-by-step explanation:

the quadrant is facing upwards

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value