E Question Help Challenge The price of Stock A at 9 AM was $16.09. Since then, the price has been increasing at
the rate of $0.12 each hour. At noon the price of Stock B was $16.84. It begins to decrease at the
rate of $0.15 each hour. If the two rates continue, in how many hours will the prices of the two
stocks be the same?

in about ___ hours the prices of the two stocks will be the same?

If only it were that easy.  After 1.44 hours, the price of the two stocks will be the same, 16.62.

Step-by-step explanation:

Let t be the time (in hours) after noon.

Stock(A) = 16.09 + 0.12 (t +3)

Stock(B) = 16.84 - 0.15t

Stock(A) = Stock(B)

16.09 + 0.12 (t+3) = 16.84 - 0.15t

16.09 + 0.12t + 0.36 = 16.84 - 0.15t

0.27t = 0.39

t=1.44 hours

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

you never say the total so we cant find the percentage used for petrol

step-by-step explanation: