what is the equation in point slope form of the line that is parallel to the given line and passes through the point (-3,1)?

Because you didn't give the line, it is impossible to write it completely. However, the line would be y - 1 = m(x + 3), in which m is the slope in the line.

We know this firstly because parallel lines have the same slope. So whatever the slope is to the given line, it must match the point-slope form.

So, we'll call this mystery slope m and then use the point in plug in the point into point-slope form.

y - y1 = m(x - x1)

y - 1 = m(x - -3)

y - 1 = m(x + 3)

b is the answer that makes most sense

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.