Juan had $24400 and chose to split the money into two different mutual funds. During the first year, Fund A earned 4% interest and Fund B earned 6% interest. If he received a total of $1166 in interest, how much had he invested into each account?

Juan invested $14,900  in Fund A and $9,500 in Fund B.

Step-by-step explanation:

Let x= Amount invested in Fund A .

Since , total amount invested = $24400

Then,  Amount invested in Fund B = 24400-x

Fund A earned 4% interest and Fund B earned 6% interest.

Interest earned by Fund A= 4% of x = 0.04 x

Interest earned by Fund B= 6% of x = 0.06 ( 24400-x)

= 0.06(24400)-0.06x

= 1464-0.06x

Total interest = 0.04x+1464-0.06x= 1464-0.02x

If he received a total of $1166 in interest, then

So, Amount invested in Fund A = $14900

Amount invested in Fund B = $( 24400-14900  ) = $9500

Hence, Juan invested $14,900  in Fund A and $9,500 in Fund B.

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.