A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=72t-16t^2. After how long will it reach its maximum height?

h(x) = 72t - 16t^2 h in feet - t in secondsThis is a formula that models the velocity of a thrown ball.When the ball has reached the maximum height acceleration is 0.The formula for the acceleration for this equation is the derivative of the original equation.This equation is 72 - 32t.Set the equation to 0.0 = 72 - 32t t in seconds32t = 72t = 2.25 seconds.Subtitute 2.25 into the original equation.72(2.25) - 16(2.25^2) = h in feet162 - 16(5.0625) = h in feet162 - 81 = h in feet81 feet = h

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