A rectangle has a length of five inches more than its width it's area is 24 square inches find the dimensions of the rectangle? A. width=3 in length=4 in
B. width=3 in length= 8 in
c. width=4 in length= 5 in
d. width=8 in length =2 in

Width = x

Length = x + 5

Area = 24 square inches

Area = length times width or A = lw for short.

24 = x(x + 5)

24 = x^2 + 5x

x^2 + 5x - 24 = 0

Factor left side.

(x - 3)(x + 5) = 0

Set each factor to 0 and solve for x.

x - 3 = 0

x = 3

x + 5 = 0

x = -5

We must reject x = -5 because we are asked to find the dimensions of the rectangle and dimension cannot be negative.

So, the width is 3 inches and the length is 5 more than 3 inches or 8 inches.

B

it has changed from the width and the height.

step-by-step explanation:

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: