Line v passes through point (6, 6) and is perpendicular to the graph of y = 34x – 11. Line w is parallel to line v and passes through point (–6, 10). Which is the equation of line w in slope-intercept form? A. y = 34x + 2
B. y = –34x + 2
C. y = 43x + 2
D. y = –43x + 2
A B C OR D WHICH ONE

y = (1/34)x + 346/34

Step-by-step explanation:

We are told that; Line v passes through point (6, 6) and is perpendicular to the graph of y = 34x – 11

Now, for a line to be perpendicular to another, it means the slope of one will be the negative reciprocal of the other.

Intercept of y = 34x – 11 will be; m = 34

Thus, slope of v is; -1/34

Now, Line w is parallel to line v and passes through point (–6, 10).

Since the slope of v = -1/34, it means the slope of w will be -1/34 because parallel lines have the same slope.

Thus, using slope intercept form, the equation of line w is;

y - 10 = (-1/34)(x - (-6))

y - 10 = x/34 + 6/34

Multiply through by 34 to get;

34y - 340 = x + 6

34y = x + 346

y = (1/34)x + 346/34

x/3-10=8

x/3=18

x=48

9x