Identify the equation for the graph shown. A)
y = x - 4
B)
y = 5x - 2
4-3x6
D)
y = 2x - 5

(D) y = 2x - 5

Step-by-step explanation:

First locate where the line touches the y axis or vertical axis. Then find the rise over run or rate of change (slope) by using the triangle method.

I call this the triangle method because it involves drawing vertical(up, and down), and horizontal(left, and right) lines from the original or diagonal line (hypotenuse or longest line) to create a right (90 degree, because the angle between them forms a square) triangle. First draw a line going to the right from a point on the original line, and form a triangle by connecting the next point with a line going up, and down (vertical line) with the line going to the right (horizontal line)

Then count the units of the vertical line and divide them by the units counted by the horizontal line.

This is k(for constant) or m(slope or steepness of a graph ) = change in or rise of y divided by the change in or rise of x = ∆y(change in or rise of y)/∆x(change in or run of x).

For this graph, starting from -5 or the point where the line touches the y axis. Draw a line going up 1 square to the right, and another going up 2 squares. Repeat this, and you will realise that it's the same pattern every time. Because the line goes up 2 squares, every time it goes to the right 1 square. There is a change of 2 in y every change of 1 in x or rise of 2 for every run of 1. Therefore, the slope is 2/1 = 2. Then since we know the graph touches the y axis at -5, y = 2x - 5

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°