Solve the system of equations.
y = 6x + 13
y = 2x + 1

x=-3. y=-5

Step-by-step explanation:

Equating both equations,

6x + 13 = 2x + 1

6x - 2x = 1 - 13

4x = -12

x = -3

Plug in the value of x in the given first equation,

y = 6* (-3) + 13 = -18 + 13 = -5

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

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