Write the equation of the line in slope-intercept form that passes through the point (-2, 5) and is parallel to the line y= -3x+2

y=-3x-1

Step-by-step explanation:

A parallel line has the same slope but different y-intercept

So we will ignore the "2" in y=-3x+2, lets plug in (-2,5) for (x,y)

5=-2(-3)+b

5=6+b    subtract six from both sides

5-6=6-6+b

b=-1    we have our "b' in y=mx+"b"

our new equation is gonna be

y=-3x-1

i dont know

step-by-step explanation: