The sum of three consecutive even integers is 72 Letx represent the first integer, x + 2 represent the second integer, and x + 1 represent the third integer
Which equation can be used to find the first integer?
2x + 64 = 72
3x + 72 - 2x + 6
3x + 2x + 6
3x + 6 = 72

3x+6=72

Step-by-step explanation:

1.st integer is x

2.nd is  x+2

Thrd is x+4

So the sum is x+x+2+x+4=3x+6=72

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2