What is the equation of the line shown? what is the equation of a parallel line with a y-intercept of -1?

y = -⅓x + 1.

y = -⅓ - 1

Step-by-step explanation:

The equation of the line shown can be expressed in slope-intercept form as .

b = y-intercept, which is where the line intercepts the y-axis.

The line intercepts the y-axis at 1. Therefore b = 1.

m = slope = rise/run = .

Substitute b = 1 and m = -⅓ into y = mx + b to get the equation of the line shown. Thus, the equation would be:

y = -⅓x + 1.

The equation of a line with y-intercept (b) of -1 that is parallel to the line shown, would have the same slope as the line shown but different y-intercept.

Thus, the slope of the line shown is m = -⅓, this would also be the slope of the line parallel to it.

Therefore, substitute m = -⅓ and b = -1 into y = mx + b.

y = -⅓x + (-1)

y = -⅓ - 1

The equation of the line with y-intercept big -1 that is parallel to the line shown on the graph, is y = -⅓ - 1

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step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)