If f (x) = (x2 – 2)3 +6, what is the rule for the inverse of f? o f-1 (2) = Y. - 2 + 6
o f-1(2) = y2 - 2 - 6
f'(x) = yx – 6+2
o f-1(x) = y2 - 6 - 2

a. -0.3 > -0.33

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this