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Mathematics, 30.10.2020 16:50 1234fatimasm

\dfrac{6}{3}+\left(-\dfrac{1}6\righ t)= 3 6 +(βˆ’ 6 1 )=start fraction, 6, divided by, 3, end fraction, plus, left parenthesis, minus, start fraction, 1, divided by, 6, end fraction, right parenthesis, equals

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\dfrac{6}{3}+\left(-\dfrac{1}6\righ t)= 3 6 +(βˆ’ 6 1 )=start fraction, 6, divided by, 3, end fracti...
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