To rent a certain meeting room, a college charges a reservation fee of $41 and an additional fee of $8.30 per hour. The history club wants to spend at most $99.10 on renting the meeting room. What are the possible amounts of time for which they could rent the meeting room? Use t for the number of hours the meeting room is rented, and solve your inequality fort.

Step-by-step explanation:

let the total charges be y

and the number of hours be t

the total cost can be modelled linearly as

y=mt+c

given that

c=$41

m=$8.30

Therefore for y=99.10, we want to solve for t

99.1=8.3t+41

solve for t

99.1-41=8.3t

58.1=8.3t

t=58.1/8.3

t=7

therefore the time is 7hours max

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this