HELP ASAP TIMED
PLEASE Find the value of the expression. d 27a^0c^3 for a= 2/3 , c=−1/3

-1

Step-by-step explanation:

27a^0c^3

27(2/3)^0(-1/3)^3

Apply the product rule to 2/3.

27(2^0/3^0)(-1/3)^3

Anything raised to 0 is 1.

27(1/3^0)(-1/3)^3

Anything raised to 0 is 1.

27(1/1)(-1/3)^3

Divide 1 by 1.

27 x 1(-1/3)^3

Multiply 27 by 1.

27(-1/3)^3

Apply the product rule to -1/3.

27[(-1)^3(1/3)^3]

Apply the product rule to 1/3.

27[(-1)^3(1^3/3^3)]

Raise -1 to the power of 3.

27(-1^3/3^3)

One to any power is one.

27(-1/3^3)

Raise 3 to the power of 3.

27(-1/27)

Move the leading negative in -1/27 into the numerator.

27(-1/27)

Cancel the common factor and rewrite the expression.

-1

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29