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Mathematics, 30.10.2020 01:00 mmblair14

An object is launched at 20 m/s from a height of 65 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.912 + 20t + 65. What is the object's maximum height?

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An object is launched at 20 m/s from a height of 65 m. The equation for the height (h) in terms of t...
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