Write the equation of the line that is parallel to y = 9x+ 4 and crosses the y-axis at -3.

9514 1404 393

  y = 9x -3

Step-by-step explanation:

The given line is in "slope-intercept form"

  y = mx + b

where m is the slope and b is the y-intercept (where it crosses the y-axis).

In your given line, we have ...

  m = 9, b = 4

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A parallel line will have the same slope, so we know that the line you want has m = 9. You are told to make the line cross the y-axis at -3, so that makes b = -3. Putting these values into the slope-intercept form gives the desired equation:

  y = 9x -3

_____

The attached graph is intended to show the lines are parallel and the equation given here meets the requirement for a crossing of the y-axis at -3. The vertical and horizontal scales are different in order to better show these things.

a) 0,0; 1,1; and 2,2

step-by-step explanation:

these have the exact same coordinates, thus they are the correct function.

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16