Given that z is a standard normal random variable, what is the value of z if the area to the left of z is 0.9382: a. 1.8
b. 1.54
c. 2.1
d. 1.77

1.54

Step-by-step explanation:

Given that :

Z = normal random variable

Area to the left of z = 0.9382

For a random normal distribution ;

P(Z < x) = 0.9382

Using the Z table (standard normal distribution table) ;

Locating the probability value (0.9382) on the table and picking the intersecting z value both horizontally and vertically :

Horizontal value = 1.5

Vertical value = 0.04

Horizontal + vertical = (1.5 + 0.04) = 1.54

sorry i need the points

step-by-step explanation:

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17

step-by-step explanation:

51/3=17

thus 17 is your answer.