A scuba diver dove 63 feet below the ocean's surface. He then ascended 27 feet to under an underwater cave. What is the depth of the entrance of the cave?

First, we need to define a zero in the vertical position.

Let's define the zero as the ocean's surface.

"A scuba diver dove 63 feet below the ocean's surface."

Then the scuba's position at this moment was:

P = -63ft

"He then ascended 27 feet to under an underwater cave."

The new position will be:

P = -63ft + 27ft = -36ft

And here is the entrance of the underwater cave.

Then we can conclude that the depth of the entrance of the underwater cave is 36ft deep, or that the entrance is 36ft below the ocean's surface.

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

idk

step-by-step explanation:

use that smart brain