You reflect triangle pqr, with verticles p(-2 -4) q(-3 -1) and r(-4 -4) across the y-axis to get triangle p'q'r' what are the cooridinates of triangle p'q'r'

see explanation

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , thus

p(- 2, - 4 ) → p'(2, - 4 )

q(- 3, - 1 ) → q'(3, - 1 )

r(- 4, - 4 ) → r'(4, - 4 )

function 2 has a greater rate of change than function 1

function 2 has a greater y-intercept than function 1

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl