How large should n be to guarantee that the Trapezoidal rule approximation to integral^8_3 (-x^4 + 22x^3 - 144x^2 + 4x + 5)dx is accurate to within 0.0001. How large should n be to guarantee that the Simpsons Rule approximation to integral^8_3 (-x^4 + 22x^3 - 144x^2 + 4x + 5)dx is accurate to within 0.0001.

Midpoint Rule: If |f"(x)| less than or equal to K for a less than or equal to x less than or equal to b then |ET| less than or equal to K(b - a)^3/12n^2

Simpson's Rule: If |f^(iv) (x)| less than or equal to K for a less than or equal to x less than or equal to b then |ES| less than or equal to K(b - a)^5/180n^4

give more details

step-by-step explanation:

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles

idc

step-by-step explanation:

idk