Write a polynomial fx that satisfies the given conditions. Express the polynomial with the lowest possible leading positive integer coefficient. Polynomial of lowest degree with lowest possible integer coefficients, and with zeros 5-32i and 0 (multiplicity 4).

f(x)=

Step-by-step explanation:

Find the question attached.

Given the zero of the polynomial 5+3i and 0, this means that (x-0) and (x-(5+3i)) are factors

Multiplying the factors together we have;

= x((x-(5+3i))

= x(x-5-3i)

= x²-5x-3xi

Hence the polynomial expression of the zeros is x²-5x-3xi

the correct answer is 5 6 and 7

i think the correct option is the second option.