explain 18. If the likelihood of a tagged order form is 0.1, what is the probability that there are three tagged order forms in the sample of four

The probability is 0.0036

Step-by-step explanation:

Let the probability of tagged order form be p = 0.1

probability of untagged = q = 1 -0.1 = 0.9

To find the probability in the question, we apply the Bernoulli approximation of the binomial distribution

That will be;

P( X = 3) = 4 C 3 •p^3 • q

P(X = 3) = 4 * (0.1)^3 * 0.9

P(X = 3) = 0.0036

for a it would be 24 children.

for b i don't understand the question. is it saying for each individual person they pick 5 reds to 7 greens or is it the whole group. clarify and i hope this can you.

step-by-step explanation:

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110