A rocket is launched from a tower. The height of the rocket, y in feet, 15 related to the time after launch, x in seconds, by the given equation. Using
this equation, find the maximum height reached by the rocket, to the nearest
tenth of a foot.
y = –16x2 + 228x + 71

Select the correct answer. given: ∆abc with prove: statement reason 1. given 2. ∠cab ≅ ∠edb ∠acb ≅ ∠deb if two parallel lines are cut by a transversal, the corresponding angles are congruent. 3. ∆abc ~ ∆dbe aa criterion for similarity 4. corresponding sides of similar triangles are proportional. 5. ab = ad + db cb = ce + eb segment addition 6. substitution property of equality 7. division 8. subtraction property of equality what is the missing statement in the proof? scroll down to see the entire proof.