In ΔBCD, \overline{BD} BD is extended through point D to point E, \text{m}\angle BCD=(2x-1){\circ}m∠BDC=(2x-1) ° ,\text{m}\angle CDE=(7x-19)^{\circ}m∠CDE=(7x-19) ° , and \text{m}\angle DBC = (x+10)^{\circ}m∠DBC=(x+10) ∘ . Find \text{m}\angle CDE.∠CDE.

answer: 7270

step-by-step explanation:

your answer is b ^w^ hope i

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6