F(x) = x^3- 9x
What is the average rate of change of f over the interval [1, 6]

Step-by-step explanation:

This is the formula for the average rate of change

over the interval (a, b)

a and b are x values

f(a) ad f(b) think of them as y values

Start calculating f(a) and f(b) a=1 b=6

replace all x's in formula with a, (1)

f(1)=1³-9(1) = 1-9= -8    f(1) = -8

Now do : b (6)

f(6) = 6³ - 9 (6) = 216-54=162 f(6) = 162

now plug everything into your equation

average rate of change.

notice the 162 - (-8) In math there is no subtraction, and you would change it to + and when you do that you much change the sign of the next value making -8 a +8.

Hope this helps. Good luck!

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.