A worker is taking cases of screws on a lift. Each case weighs 47 pounds and the worker weighs 182 pounds. the lift has a weight limit of 2700 pounds Write an inequality that describes the number of cases he can safely take on each
trip. What is the maximum amount of cases he can take?

a) The inequality representing the number of cases he can take =

180 + 47c ≤ 2700

b) 53 cases

Step-by-step explanation:

A worker is taking cases of screws on a lift. Each case weighs 47 pounds and the worker weighs 182 pounds. the lift

has a weight limit of 2700 pounds

a) Write an inequality that describes the number of cases he can safely take on each trip.

Let us represent the number of cases as c

hence,

180 + 47 × c ≤ 2700

= 180 + 47c ≤ 2700

b) What is the maximum amount of cases he can take?

The maximum amount of cases he can take =

180 + 47c ≤ 2700

180 + 47c = 2700

Collect like terms

47c = 2700 - 180

47c = 2520

c = 2520/47

c = 53.617021277 cases

c = 53 cases

The maximum number of cases he can carry is 53 cases

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.

32

step-by-step explanation: