(Part 1)What is the combined area of the two right triangles? A. 12 B. 18 C. 24 D.36 (Part 2) Whick expression gives the area of the parallelogram A. (14x6-24) square units B.(14x6-18) square units C.(8x6+36) swuare units
D. (8x6+12) square units

Part 1: D. 36

Part 2: C. (8*6 + 36) square units

Step-by-step explanation:

Part 1:

Area of a triangle = ½*base*height

The two triangles has the same height and base.

Height = 6,

Base = 6

Combined area of the two right angles = 2(½*base*height)

= 2(½*6*6)

= (6*6)

Combined area = 36 square units

Part 2:

The are of the parallelogram = area of the rectangle + the combined are of the two right triangles

The rectangle has:

length = 14 - 6 = 8

Width = 6

Area of rectangle = length * width = 8*6

Combined area of the two right triangles = 36

Therefore, the expression of the area of the parallelogram = (8*6 + 36) square units

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w