In a test with a mean of 100 and a standard deviation of 10, what is the standard deviation for a test score of 120

This question is incomplete

Complete Question

In a test with a mean of 100 and a standard deviation of 10, what is the standard score for a test score of 120?

The standard score = 2

Step-by-step explanation:

The formula for Test (T) score is given as:

T score = zσ + μ

z = Standard or z score = ??

Standard deviation (σ) = 10

Mean (μ) = 100

Test score = 120

120 = 10z + 100

120 - 100 = 10z

20 = 10z

z = 20/10

z= 2

Therefore, the standard score = 2

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;