Find the critical t-value for a 98% confidence interval estimation if the sample size equals 11. (Round your solution to 4 decimal places)

2.764

Step-by-step explanation:

Critical value = tα/2, degrees of freedom

Degrees of freedom = n - 1

n = 11

Degrees of freedom = 11 - 1

= 10

tα/2 = 100 - 98%/2

= 2%/2

= 1%

= 0.01

Critical value = 0.01, 10

Using the Critical T value table, the Critical T value for

two tails( a degree of significance of 0.02 and degree of freedom of 10) or one tail (0.01, 10) = 2.764

10 miles

step-by-step explanation:

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.