The average cost of a compact car at a certain dealership over the last 10 years has ranged from $15,000 to $24,500. Suppose you were going to plot these points on a coordinate grid. (a) What is a good scale [range] would be good to use for the y-axis to make a nicely sized graph? Explain your reasoning. (b) What is a good interval [step size] would be good to use for the y-axis to make a nicely sized graph? Explain your reasoning. (c) What is a good scale [range] would be good to use for the x-axis to make a nicely sized graph? Explain your reasoning. (d) What is a good interval [step size] would be good to use for the x-axis to make a nicely sized graph? Explain your reasoning. Note: The step size the distance between the marks on the graph, and the range is the maximum and minimum values (ex: -10 to 10).

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

i don’t see a picture

yes, gavin is right.

step-by-step explanation:

gavin is correct. 

this problem is about converting 9% per year to how many percent per quarter. the rate is still the same. it only differed in the time period. so, through dimensional analysis,

9% per year  × (1 year / 4 quarters) = 2.25% per quarter

if he was asked to convert 9% per year to how many percent per quarter  compounded quarterly, then you will not simply divide by four. this is because compounding is not linear.

hope this , have a good day. c;

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft