Annie needs to change the price of a pile of sweaters. She is told to apply a discount function on each price, d(p)=.85p d
(
p
)
=
.85
p
, and then increase the resulting price: r(p)=p+10
r
(
p
)
=
p
+
10
.

What is the function that Annie can use to calculate both price changes?

f(p)=0.85p+(p+10)
f of p is equal to 0 point 8 5 p plus open paren p plus 10 close paren

r(d(p))=0.85p+10
r times open paren d times p close paren is equal to 0 point 8 5 p plus 10

f(p)=0.85p⋅(p+10)
f of p is equal to 0 point 8 5 p times open paren p plus 10 close paren

d(r(p))=0.85p+8.50
d times open paren r times p close paren is equal to 0 point 8 5 p plus 8 point 5 0

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

$15.40 per mile

step-by-step explanation:

you have to round up to 4 because 6 is over 5 so you have to round the 3 up to 4

multiply each one by 3.14

step-by-step explanation: