What is the equation of the line that is parallel to y=2x+2 but passes through the point (1,6)

y=2x+4

Step-by-step explanation:

y=2x+2

Gradient = 2

Gradient of the line passing through point (1,6)

= 2

i.e it is parallel to line y=2x+2.

Equation of the line is given as:

y - 6 = 2(x - 1)

y - 6 = 2x -2

y = 2x -2 + 6

y = 2x + 4

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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