Suppose the mean checkout tab for all customers at a large supermarket equals $65.12 with a standard deviation of $21.45. Twenty-three out of 100 times when a random sample of 45 customer tabs is selected, the sample mean should exceed what value

Step-by-step explanation:

Suppose the mean checkout tab for all customers at a large supermarket equals $65.12 with a standard deviation of $21.45. Twenty-three out of 100 times when a random sample of 45 customer tabs is selected, the sample mean should exceed what value

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00