Kelly needs to travel 12 miles. Taxi A charges $3.00 plus $0.30 every 1/9 mile. Taxi B charges $3.25 plus $0.20 every 1/9 mile. How much money (in dollars) does kelly save by using taxi B instead of taxi A?

$10.55

Step-by-step explanation:

Total miles traveled = 12miles

If taxi A charges $0.3 for every 1/9 mile, then for 12 Miles, he will charge;

12×0.3/(1/9)

= 12×0.3×9

= 108×0.3

= $32.4

Amount charged initially = $3.00

Total charge by Taxi A = $32.4+$3.00

Total charge by Taxi A = $35.4

If taxi B charges $0.2 for every 1/9 mile, then for 12 Miles, he will charge;

12×0.2/(1/9)

= 12×0.2×9

= 108×0.2

= $21.6

Amount charged initially = $3.25

Total charge by Taxi B = $21.6+$3.25

Total charge by Taxi B = $24.85

Total money saved by Kelly = Amount charged by Taxi A - Amount charged by Taxi B

Total money saved by Kelly = $35.4-$24.85

= $10.55

Hence Kelly saved $10.55 using taxi B

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead